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Voltage Drop Calculator

Calculate voltage drop across cables and wires for copper and aluminum conductors.

Component Values

V

Results

Cable Resistance (round trip)0.1344 Ω
Voltage Drop1.3440 V

AWG Wire Size Reference

AWGmm²Copper (Ω/km)Aluminum (Ω/km)
105.2613.195.04
123.3095.088.01
142.0818.0712.73
161.30912.8320.24
180.82320.4132.20
200.51832.4351.16
220.32651.5381.29
240.20581.95129.27
260.129130.23205.43
280.081207.41327.16
300.0509330.06520.63

Understanding voltage drop in cables

Voltage drop is the reduction in voltage across a conductor due to its resistance. Every wire has resistance proportional to its length and inversely proportional to its cross-sectional area. The total cable resistance for a round-trip circuit is R = p x 2L / A, where p is the material resistivity, L is the one-way length, and A is the cross-section.

The IEC 60364 standard recommends that voltage drop should not exceed 3% for lighting circuits and 5% for other loads. The NEC similarly recommends 3% for branch circuits and 5% total. Excessive voltage drop wastes energy as heat in the cable and can cause equipment to malfunction, especially motors and sensitive electronics.

Copper (p = 1.68e-8 ohm.m) is the most common conductor material due to its low resistivity. Aluminum (p = 2.65e-8 ohm.m) has about 60% higher resistivity but is lighter and cheaper, making it popular for overhead power lines and large installations. To compensate, aluminum cables use a larger cross-section than copper for the same current capacity.

For long cable runs -- solar panel arrays, industrial plants, EV charging stations -- voltage drop calculation is critical. Increasing wire gauge (larger cross-section) reduces resistance and voltage drop. The trade-off is cost and weight. Always verify that your cable sizing satisfies both current capacity (ampacity) and voltage drop requirements.

Cable Resistance

R_cable = ρ × 2L / A

Voltage Drop

V_drop = I × R_cable

Drop Percentage

Drop% = (V_drop / V_source) × 100

Key Points

  • Voltage drop is proportional to current and cable length
  • IEC 60364: max 3% for lighting, 5% for other circuits
  • Copper has ~40% less resistivity than aluminum
  • Doubling the cross-section halves the voltage drop
  • Round-trip length = 2 x one-way cable length

Applications

  • Residential and commercial wiring design
  • Solar panel array cable sizing
  • EV charging station installation
  • Industrial plant power distribution

AWG quick-reference table (copper wire)

AWGDiameter (mm)Area (mm²)Max Current (A)Resistance (mΩ/m)
102.595.26303.28
122.053.31205.21
141.632.08158.28
161.291.311313.2
181.020.821020.9
200.810.52733.2
220.640.33552.9
240.510.20384.2

NEC / IEC voltage drop guideline

NEC/IEC guideline: voltage drop should not exceed 3% for branch circuits or 5% total (feeder + branch combined). For sensitive electronics — microcontrollers, sensors, audio — keep drop below 2% to avoid measurement errors and logic instability.

Practical example

12V LED strip — 3A, 5m run (18 AWG copper)

Calculate round-trip voltage drop for a 5-metre LED strip cable run using 18 AWG copper wire.

R = 2 × 5m × 20.9 mΩ/m = 209 mΩ
Drop = 3A × 0.209Ω = 0.63V (5.2%) — exceeds 5% limit
Solution: upgrade to 16 AWG (13.2 mΩ/m) → drop = 0.40V (3.3%)

The factor of 2 everyone forgets

The mistake everyone makes is forgetting the factor of 2. Current leaves the source, runs down the wire to the load, and comes all the way back — so the copper it travels through is twice the one-way length. Drop the 2 and your calculated drop is half of reality, which is exactly the error that leaves an LED strip dim at the far end.

Voltage drop (round trip)

Vdrop = 2 × ρ × L × I / A

L is the one-way run; the 2 covers the return leg. ρ_copper = 1.68×10⁻⁸ Ω·m at 20 °C, aluminium = 2.82×10⁻⁸ Ω·m — aluminium needs about 60% more cross-section to match copper.

AWG to mm² reference (copper resistance)

European installers spec cable in mm², American ones in AWG, and a voltage-drop number means nothing until you've pinned the cross-section. The copper resistance column is the one-way mΩ per metre at 20 °C — double it for the round trip in the formula above.

AWGmm²Copper (mΩ/m)
105.263.28
123.315.21
142.088.29
161.3113.2
180.82321.0
200.51833.3
220.32652.9
240.20584.2

Need the full AWG list with ampacity and aluminium figures? The wire gauge calculator has it, and the resistor power calculator tells you how much heat that I²R drop actually dumps into the cable. The numbers above come straight from the American wire gauge standard.

The 3% rule and temperature derating

Electrical codes draw the line at 3%: keep the drop on any branch circuit at or below 3%, and the whole run — feeder plus branch — under 5%. For a 12 V system that 3% is only 0.36 V, which is why low-voltage runs eat cable so fast.

And the table values are cold values. Copper resistivity rises about 0.39% per °C, so a cable sitting at 70 °C — bundled in conduit on a hot day, or carrying near-rated current — has roughly 20% more resistance than the 20 °C number suggests. Size for the temperature the cable will actually run at, not the bench.

Worked examples

12 V LED strip — 5 m run at 2 A

A 5 m feed in 18 AWG (21.0 mΩ/m). Watch the round trip bite into a tight 12 V budget.

Vdrop = 2 × 5 m × 0.021 Ω/m × 2 A = 0.42 V (3.5%)
Over the 3% line. Step up to 16 AWG (13.2 mΩ/m) → 0.26 V (2.2%).

12 V RV accessory — 6 m run at 8 A

A fridge or fan wired from the battery to the back of an RV. Long automotive 12 V runs are where this hurts.

16 AWG: 2 × 6 m × 0.0132 Ω/m × 8 A = 1.27 V (10.6%) — far too much.
Use 12 AWG (5.21 mΩ/m) → 0.50 V (4.2%).

Solar panel to charge controller — 10 m at 6 A

A 12 V panel feeding a PWM controller 10 m away. Long, low-voltage runs are exactly where drop steals your harvest.

10 AWG (3.28 mΩ/m): 2 × 10 m × 0.00328 Ω/m × 6 A = 0.39 V (3.3%)
Acceptable, but an MPPT controller at higher array voltage would cut the percentage hard.

Did you know? Voltage drop in long cable runs is a critical issue in solar installations and marine/automotive wiring. A 10 m run of AWG 18 wire at 5 A can drop nearly 1 V — enough to cause a 5 V microcontroller to brown-out or an LED strip to visibly dim at the far end.